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LAPACK version 3.0
zppequ(3)

PURPOSE
  ZPPEQU - compute row and column scalings intended to equilibrate a
  Hermitian positive definite matrix A in packed storage and reduce its
  condition number (with respect to the two-norm)

SYNTAX
  SUBROUTINE ZPPEQU( UPLO, N, AP, S, SCOND, AMAX, INFO )

      CHARACTER	     UPLO

      INTEGER	     INFO, N

      DOUBLE	     PRECISION AMAX, SCOND

      DOUBLE	     PRECISION S( * )

      COMPLEX*16     AP( * )

DESCRIPTION
  ZPPEQU computes row and column scalings intended to equilibrate a Hermitian
  positive definite matrix A in packed storage and reduce its condition
  number (with respect to the two-norm). S contains the scale factors,
  S(i)=1/sqrt(A(i,i)), chosen so that the scaled matrix B with elements
  B(i,j)=S(i)*A(i,j)*S(j) has ones on the diagonal.  This choice of S puts
  the condition number of B within a factor N of the smallest possible
  condition number over all possible diagonal scalings.

ARGUMENTS
  UPLO	  (input) CHARACTER*1
	  = 'U':  Upper triangle of A is stored;
	  = 'L':  Lower triangle of A is stored.

  N	  (input) INTEGER
	  The order of the matrix A.  N >= 0.

  AP	  (input) COMPLEX*16 array, dimension (N*(N+1)/2)
	  The upper or lower triangle of the Hermitian matrix A, packed
	  columnwise in a linear array.	 The j-th column of A is stored in
	  the array AP as follows: if UPLO = 'U', AP(i + (j-1)*j/2) = A(i,j)
	  for 1<=i<=j; if UPLO = 'L', AP(i + (j-1)*(2n-j)/2) = A(i,j) for
	  j<=i<=n.

  S	  (output) DOUBLE PRECISION array, dimension (N)
	  If INFO = 0, S contains the scale factors for A.

  SCOND	  (output) DOUBLE PRECISION
	  If INFO = 0, S contains the ratio of the smallest S(i) to the
	  largest S(i).	 If SCOND >= 0.1 and AMAX is neither too large nor
	  too small, it is not worth scaling by S.

  AMAX	  (output) DOUBLE PRECISION
	  Absolute value of largest matrix element.  If AMAX is very close to
	  overflow or very close to underflow, the matrix should be scaled.

  INFO	  (output) INTEGER
	  = 0:	successful exit
	  < 0:	if INFO = -i, the i-th argument had an illegal value
	  > 0:	if INFO = i, the i-th diagonal element is nonpositive.